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3 years ago

What are the roots of this equation?

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

4 0

Answer:

x = 2 ± (i)√5 (Answer b)

Step-by-step explanation:

x²-4x+9=0 can be solved in a variety of ways; the first two that come to mind that are also appropriate are (1) completing the square and (2) using the quadratic formula.

Completing the square is fast here:

Rewrite x²-4x+9=0 as x²-4x +9=0

Identify the coefficient of the x term: it is -4

Take half of that, obtaining -2

Square this result, obtaining 4

Add 4 to x²-4x +9=0, in the blank space in the middle, and then subtract 4: x²-4x +4 -4 +9=0

Rewrite x²-4x +4 as the square of a binomial:

(x - 2)² - 4 + 9 = 0 → (x - 2)² = -5

Take the square root of both sides: x - 2 = ±√(-5) = ± (i)√5

Then x = 2 ± (i)√5

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4 years ago

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Vadim26 [7]

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Infinite solutions

Step-by-step explanation:

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