The y-value is the one on the right. Therefore, the y-value of P is 6. Following the rule, the y-value of P' is 6-16= -10.
Answer:
(5,5)
Step-by-step explanation:
You draw a graph and put an x where (5, -3) is and then from that point, you go up by 8 units
Answer:
a = -0.3575
Step-by-step explanation:
The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.
The points A and B are located where

This gives


Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

Thus the coordinates of B are:

Now this point B lies on the parabola, and therefore it must satisfy the equation 
Thus

Therefore


The side lengths are 2 units and 4 units. Do you need work?