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ivann1987 [24]
2 years ago
11

Jackson finds a cat stuck in a 20ft tree. Luckily he has a 25foot ladder. If the ladder leans against the tree leaving 6ft of sp

ace between, will it be long enough for Jackson to rescue the cat.
Mathematics
1 answer:
Temka [501]2 years ago
8 0
Hello!

This makes a triangle

The cat is 20 ft high

The triangle is 20 feet high

The is 6 ft between the ladder and the tree

The base is 6 ft long

You use the Pythagorean theorem to solve this

a^{2} + b^{2} =c^{2}

a and b are the base and height

put in the values you know

6^{2} + 20^{2} = c^{2}

square the numbers

36 + 400 = c^{2}

Add

436 = c^{2}

Take the square root of 436

20.9 = c

Since this is lower than the length of the ladder the ladder is long enough

The answer is yes

Hope this helps!
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3 years ago
Plz plz plz help me with this
erica [24]
This question wants you to find a common denominator for the fractions.
This means finding the LCM, least common multiple, for 21 and 9.
This can be done by listing the multiples for each number until they meet at a common one.

9:
9
18
27
36
45
54
63

21:
21
42
63

This means the LCM of 21 and 9 is 63.
So the lowest possible common denominator is 63.

21 • 3 = 63
So you have to multiply the numerator of 2/21 by 3 as well.
2 • 3 = 6
2/21 = 6/63

Now do the same for 1/9.
9 • 7 = 63
Multiply the numerator, 1, by 7.
1 • 7 = 7
1/9 = 7/63

So in the first blanks, you would put 6/63 for what 2/21 is equal to and 7/63 for what 1/9 is equal to.

7/63 is greater than 6/63.
7/63 > 6/63
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So 2/21 < 1/9 is the answer to the last blank.

Hope this helps!
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3 years ago
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