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ivann1987 [24]
3 years ago
11

Jackson finds a cat stuck in a 20ft tree. Luckily he has a 25foot ladder. If the ladder leans against the tree leaving 6ft of sp

ace between, will it be long enough for Jackson to rescue the cat.
Mathematics
1 answer:
Temka [501]3 years ago
8 0
Hello!

This makes a triangle

The cat is 20 ft high

The triangle is 20 feet high

The is 6 ft between the ladder and the tree

The base is 6 ft long

You use the Pythagorean theorem to solve this

a^{2} + b^{2} =c^{2}

a and b are the base and height

put in the values you know

6^{2} + 20^{2} = c^{2}

square the numbers

36 + 400 = c^{2}

Add

436 = c^{2}

Take the square root of 436

20.9 = c

Since this is lower than the length of the ladder the ladder is long enough

The answer is yes

Hope this helps!
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Heelp me im struggling
olga nikolaevna [1]

Answer:

b. -30

Step-by-step explanation:

the reason why it is B is because the operation in front of the number that stands alone without being a constant number that increases (or decreases) like the number 2, it has an x next to it which means that the number 2 is going to increase at a constant rate.

<em>hope it helps:)</em>

6 0
3 years ago
nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. in the first part of the race, her av
Nataliya [291]
Total distance 5 km; at 5km / 0.65 h =

Second part distance: x; at 6 km/h, during t2

First part distance: 5 - x; at 8.75 km/h, during t1

V = d/t ⇒ t = d/V

t2 = x/6
t1=[5-x]/8.75

t2 + t1 = 0.65

x/6 + [5-x]/8.75 = 0.65

x/6 + 5/8.75 - x/8.75 = 13/20

 x/6 - x/8.75 = 13/20 - 5/8.75

x/6 - 4x/35 =13/20 - 20/35

35x - 24x = (35*6)(35*13 - 20*20)/(20*35)

11 x = 16.5
x = 16.5/11 = 1.5 km












5 0
3 years ago
One manufacturer is calculating the trade discount on a dog kennel with a list price of $257 and a trade discount series of 12/1
nataly862011 [7]
79.55449 your welcome this is totally wrong lol sos
6 0
3 years ago
Stock bottles should be moved on the shelves A. by placing new stock behind old stock so stock closest to expiration gets used f
Vinvika [58]
A. By placing new stock behind old stock
6 0
2 years ago
If 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), w
Yuliya22 [10]

The value of a is 80

Step-by-step explanation:

The distance of a point (x_0,y_0) from the y-axis can be written as

d_y = |x_0|

because the x-coordinate of the y-axis is zero.

Similarly, the distance of a point (x_0,y_0) from the x-axis can be written as

d_x=|y_0|

Since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

d_A = |-30|=30

- The distance of point B (a,a) from the x-axis can be written as

d_B = |a| = a

Since a>0.

We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

\frac{2}{3}d_A = \frac{1}{4}d_B

Therefore,

\frac{2}{3}(30)=\frac{1}{4}a

And solving for a,

20=\frac{1}{4}a\\a=80

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

8 0
3 years ago
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