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gulaghasi [49]
3 years ago
13

Find the lengths of the diagonals of rectangle WXYZ.

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

According to the question,

  • WY = (6x - 7) units
  • XZ = (3x + 2) units

As we know that,

❖ Diagonals of a rectangle are equal.

\\ \twoheadrightarrow \sf { WY = XZ} \\

\\ \twoheadrightarrow \sf { 6x - 7 = 3x +2} \\

\\ \twoheadrightarrow \sf { 6x - 3x = 2  + 7} \\

\\ \twoheadrightarrow \sf { 3x = 9} \\

\\ \twoheadrightarrow \sf {x =\dfrac{9}{3} } \\

\\ \twoheadrightarrow \bf\underline { x = 3} \\

Therefore,

\\ \twoheadrightarrow \sf { WY \; \& \; XZ = (3x - 2) \; units} \\

  • Since, WY = XZ

\\ \twoheadrightarrow \sf { WY \; \& \; XZ = 3(3) + 2 \; units} \\

\\ \twoheadrightarrow \sf { WY \; \& \; XZ = 9 + 2 \; units} \\

\\ \twoheadrightarrow \bf\underline { WY \; \& \; XZ = 11\; units} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>each</u><u> </u><u>diagonal</u><u> </u><u>is</u><u> </u><u>1</u><u>1</u><u> </u><u>units</u><u>.</u><u> </u>

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Step-by-step explanation:

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what variable expression should you subtract from both sides of the equation so that you are left with no variables on the right
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SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

What variable expression should you subtract from both sides of the equation so that you are left with no variables on the right-hand side?

The variable expression is: subtract 5x from both sides so that you are left with no variables on the right-hand side

\begin{gathered} 6x\text{ - 10 = 5x + 15} \\ \text{Subtract 5 x from both sides, we have that:} \\ 6x\text{ - 5x - 10 = 5x - 5x + 15} \\ x\text{ - 10 = 15} \\ \text{Now, add 10 to both sides, we have that:} \\ x\text{ - 10 + 10 = 15 + 10} \\ x\text{ = 25} \\ \text{check:} \\ 6x\text{ - 10 = 5x + 15} \\ \sin ce,\text{ x = 25 , we have that:} \\ 6(25)\text{ - 10 = 5(25) + 15 } \\ 150\text{ - 10 = 125+ 15= 140 ( COR}\R ECT) \end{gathered}

CONCLUSION:

The final answer is:

x\text{ = 25}

​

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