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Tresset [83]
3 years ago
7

Select two ordered pairs that satisfy the function y = –4x – 1.

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0
X = -0.25 and x = -2^-2
I’m not sure if this helps
gogolik [260]3 years ago
3 0

Answer:

(-0.25,0) and (0,-1)

Step-by-step explanation:

I used a graphing calculator.

Put function the the calculator

then ind two points on the function and that is your answer

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Answer:

12: 32

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Find the value of x and y<br> 3х<br> 20<br> 25<br> 18<br> бу -2<br> Х=<br> ү=
sweet-ann [11.9K]

Answer: first one =109360044xy−36453348x−2, 2nd,=3037778998,last one,=1968480790

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33x(2025186)(6y−2)−2

33x(2025186)(6y−2)−2

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Evaluate for x=20,y=25

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(3)(20)(2025186)(25)−2

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because 18 is by itself i just did Evaluate for x=18,y=18

(3)(18)(2025186)(18)−2

(3)(18)(2025186)(18)−2

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7 0
2 years ago
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

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2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

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4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
3 years ago
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