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3 years ago

Help me with this question

Mathematics

1 answer:

vladimir1956 [14]3 years ago

8 0

It is 12.56 because you nee

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What is the slope of 2x-1=-3y

torisob [31]

I think its -1 i not very smart so it probably wrong

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3 years ago

Read 2 more answers

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andrew-mc [135]

For the reaction,

$CO(g) + H_2 O(g) = CO_2(g) + H_2(g)$

Initial concentration:

0.1M , 0.1M , 0 , 0

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

(0.1 – x)M , (0.1 – x)M , xM , xM

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

$K_c = \frac{x²}{(0.1 – x)²} = 4.24$

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

a = 3.24, b = -0.848, c = 0.0424

(for quadratic equation ax² + bx+c=0)

$x = \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}$

$= > x = \frac{ - ( - 0.848 \: ± \: \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}$

$= > x = \frac{ - 0.848±0.4118}{6.48}$

$x_1 = \frac{0.848 - 0.4118}{6.48} = 0.067$

$x_2 = \frac{0.848 + 0.4118}{6.48} = 0.194$

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

$[CO_2] [H_2] = x = 0.067M$

$[CO] [H_2 O] = 0.1 - 0.067 = 0.033M$

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3 years ago

What is the standard form?

jolli1 [7]

Answer:

Standard form is a way of writing down very large or very small numbers easily. 103 = 1000, so 4 × 103 = 4000 . ... This idea can be used to write even larger numbers down easily in standard form. Small numbers can also be written in standard form.

Step-by-step explanation:

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3 years ago

How do i find the square root of a number?

elena-s [515]

The square route is what times itself can get you that number such as 64, 8*8= 64, 8 is the square route.

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3 years ago

Almost done. I need help with this part

valentina_108 [34]

Answer:

$\%Percent = 14.3\%$

Step-by-step explanation:

Required

15 is what percentage of 105

To do this, simply divide 15 by 105 multiplied by 100%.

So, we have:

$\%Percent = \frac{15}{105} * 100\%$

$\%Percent = \frac{15*100}{105}\%$

$\%Percent = \frac{1500}{105}\%$

$\%Percent = 14.3\%$ --- approximated

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3 years ago