I'm sorry, but the spinner that you choose does matter in this case.
For spinner A, there are 5 equal sections with a 1 being in only one of them as well. This gives you a

chance of landing on the number 1.
For spinner B, there are 6 equal sections with a 1 being in only one of them. This gives you a

chance of landing on the number 1 - a worse chance than if you were to use spinner A.
So for this question,
you have a better chance of landing on number 1 if you choose to use spinner A.
Explanation is given step by step just below:
tan(theta(t))=y(t)/x(t)
differentiate
sec^2(theta(t))*theta'(t)=y'(t)x(t)-y(t)x'(t)/x^2(t)
thus
theta'(t)=(y'(t)x(t)-y(t)x'(t))
divided by (x^2(t)*sec^2(θ(t))
To subtract? as minus means subract/take away?
6/10 = 0.6
0.6 × 100 = 60
Answer = B.60
~Aamira~
~Hope this helped~
Answer:
y = 5 e^r * t
Let y be the population in billions and t the value of elapsed years
7 = 5 e^r * t is the equation being used where t = 15
7/5 = e^r * t
ln 7/5 = r * t taking ln of both sides
r = .336 / 15 = .0224
y = 5 e^(.0224 t) is then our equation
Check - suppose you want y at 2020
y = 5 e^(.0224 * 20) would be the equation
y = 5 e^.449 = 7.83 billion - seems to be a reasonable answer