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Butoxors [25]
3 years ago
9

The sum of - 7/9 and 11/18 is _____

Mathematics
2 answers:
aliina [53]3 years ago
7 0
-1/6 is the answer hope this helps
ollegr [7]3 years ago
6 0

Answer:

-\frac{1}{6}

Step-by-step explanation:

Common denominator: 18

-14/18 + 11/18

= -3/18

Reduce:

-1/6

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Find f (x) = -2x+9 when x=-10
Pani-rosa [81]

Answer:

29

Step-by-step explanation:

1. plug in -10 for x

-2(-10) + 9

2. multiply -2 x -10 = 20

20 + 9

3. add 20 + 9 = 29

7 0
3 years ago
True or false: Removing the parenthesis from will change the result.
egoroff_w [7]

Answer:

true

Step-by-step explanation:

the steps won't be the same

4 0
2 years ago
Read 2 more answers
RSM HOMEWORK HELP!!!
Gnesinka [82]

Answer:

Step-by-step explanation:

∠CAB = 33       {alternate interior angles}

5x = 33 + 2x    { exterior angle equals sum of opposite interior angles}

5x - 2x = 33

3x = 33

x = 33/3

x = 11

∠B = 2x = 2* 11 = 22

∠ECB = 5x = 5*11 = 55

8 0
3 years ago
Read 2 more answers
Help please!!!!ASAP! Ill give brainliest! And 50pts!<br><br> What is the value of q?
fomenos
It is c hope this helps :)
4 0
2 years ago
Read 2 more answers
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
3 years ago
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