The expression for the distance the car travels after t seconds is d = 200t + 50t²
<h3>Equation of motion </h3>
From the question, we are to write an expression for the distance the car travels after t seconds
From the given information,
The equation for the motion of an object with constant acceleration is
d = vt + 0.5at²
For the race car,
v = 200 ft/s
a = 100 ft/s²
Putting the parameters into the equation, we get
d = 200t + 0.5(100)t²
d = 200t + 0.5 ×100)t²
d = 200t + 50t²
Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²
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Answer:
.
Step-by-step explanation:
Answer:
Step-by-step explanation:
i) the length of each side of the block is 154m.
ii) the block is a square block
iii) so the perimeter of the square block will be = 4 × length of one side.
iv) Therefore the perimeter of the square block is = 4 × 154 m = 616 m.
3 and 3/5
I believe thats a mixed number .. sorry its been so long
An exponential parent function is the option C. f(x)= 
, from the given options.
What do you mean by exponential parent function?
The formula for their parent function is y = 
, where b is any non zero constant. Below is a graph of the parent function, y = 
, which demonstrates that it will never equal 0. And at y = 1 when x = 0, y crosses the y-axis.
According to options in the given question,
We have the option below in the given question:
A. f(x) = 2^x – 3 
B. f(x) = 2^x + 2 
C. f(x) = 2^x 
D. f(x) = 2^x + 1/3
We know from the above definition that the option C. is the right answer to the given question.
Therefore, the exponential parent function is f(x)= .
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