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2 years ago

16(a+b)^2-49(a-b)^2 factorize the expression

Mathematics

1 answer:

noname [10]2 years ago

4 0

The given expression is a difference of squares, so we have

16 (a + b)² - 49 (a - b)² = 4² (a + b)² - 7² (a - b)²

… = (4 (a + b))² - (7 (a - b))²

… = (4 (a + b) - 7 (a - b)) (4 (a + b) + 7 (a - b))

… = (4a + 4b - 7a + 7b) (4a + 4b + 7a - 7b)

… = (-3a + 11b) (11a - 3b)

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The length of a picture frame is 8 inches more than the width. For what

leva [86]

Answer:

For, "x" greater than 34, the perimeter of the picture frame greater than 152 inches

Solution:

Let "x" be the width of the frame

Given that, The length of a picture frame is 8 inches more than the width

Therefore,

Length = width + 8

Length = x + 8

The perimeter of rectangle is given by formula:

Perimeter = 2(length + width)

Substituting the values we get,

Perimeter = 2(x + 8 + x)

Perimeter = 2(2x + 8)

Perimeter = 4x + 16

The perimeter of the picture frame greater than 152 inches

Perimeter > 152

Therefore, for, "x" greater than 34, the perimeter of the picture frame greater than 152 inches

Step-by-step explanation:

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2 years ago

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Simplify completely ((x2-4x+4)/(x2+10x+25)) x ((x+5)/(x2+3x-10)) ...?

vladimir1956 [14]

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2 years ago

Miya is picking up two friends to go the beach. She drives from her house to

Serga [27]

Answer:

Option (C)

Step-by-step explanation:

Coordinates of the point representing the location of Miya → (1, 10)

Coordinates of the point representing the location of Drea → (13, 1)

Coordinates of the point representing the location of Francine → (16, 1)

Coordinates of the point representing the location of Beach → (19, 4)

Distance between Miya and Drea = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

= $\sqrt{(13-1)^2+(1-10)^2}$

= $\sqrt{144+81}$

= 15 miles

Distance between Drea and Francine = $\sqrt{(16-13)^2+(1-1)^2}$

= 3 miles

Distance between Francine and Beach = $\sqrt{(19-16)^2+(4-1)^2}$

= $\sqrt{9+9}$

≈ 4.2 miles

Total distance between Miya and the beach = 15 + 3 + 4.2

= 22.2 miles

Option (C) is the answer.

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2 years ago

Use the Distributive Property to find (z−5)(z+3).

Anastasy [175]

Consider, $(z-5)(z+3)$ . Let's say $a = z-5$ then the problem reduces to $a(z+3)=za+3a$ . (Do you understand this step?)

So then replacing a again with our definition we get, $z(z-5)+3(z-5)=z^2-5z+3z-15=z^2-2z-15$ .

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2 years ago

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GalinKa [24]

Answer:

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Step-by-step explanation:

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2 years ago

16(a+b)^2-49(a-b)^2 factorize the expression​

16(a+b)^2-49(a-b)^2 factorize the expression