Answer:

Step-by-step explanation:
Hello,
a and b are the zeros, we can say that

So we can say that

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write

and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes

multiply by 3

Step-by-step explanation:


<u>Hint </u><u>:</u><u>-</u>
- To find out the equation of the line we can use the point slope form of the line which is
<u>Solution</u><u> </u><u>:</u><u>-</u>
The given point to us is ,
and the slope of the line is 4 . On using the point slope form , we have ,
<u>Hence</u><u> the</u><u> </u><u>equation</u><u> </u><u>is </u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>0</u><u> </u>
( for graph , see attachment ) .
Answer:
0.005323
Step-by-step explanation:
Use the algorithm method