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3 years ago

What is the equation of a circle with center (-3, -5) and radius 4?

Mathematics

1 answer:

o-na [289]3 years ago

8 0

Answer:

$(x+3)^{2} +(y+5)^{2} =16$

Step-by-step explanation:

the general equation of a circle is

$(x-h)^{2} + (y-k)^{2} =r^{2}$

with (h,k) being the centre of the circle and r the radius

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retta has 40 raffle tickets to sell. She is required to sell at least 15 tickets. She sells the raffle tickets for $10 each. The

Rudiy27

It should be 400 considering raffle=x×10=400

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3 years ago

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HELP ASAP!!

tensa zangetsu [6.8K]

The answef is 1.83 because if you notice all of them are being divided by 38your answer is 16.5 because youre dividing all dog food in cups by wet food 3 times like 4.5/3 is 1.5 and so on

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4 years ago

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6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

3 years ago

I have no clue what to do... please help

strojnjashka [21]

Answer:

Multiply the base by the exponent

Step-by-step explanation:

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4 years ago

What is the product of (y+3)(y^2- 3y+9)

makvit [3.9K]

Answer:

y^3+27

Step-by-step explanation:

$(y+3)(y^2-3y+9)\\$

*use box method

3 0

3 years ago