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3 years ago

Divide £24 in the ratio 1:3

Mathematics

1 answer:

Kisachek [45]3 years ago

7 0

Answer:

6, and 18

Step-by-step explanation:

A ratio of 1:3 contains 4 parts because 1+3=4.

Therefore, divide 24 by 4 to get 6.

The number is split between three parts and one part, so the parts are 3(6) and 1(6).

The parts are 6 and 18

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Convert 12 1/2% into a decimal (It isn't 12.50)<br>Convert 12 1/2% into a fraction (It isn't 25/2)

Hoochie [10]

Answer:

0.125 and 1/8

Step-by-step explanation:

To convert a percentage to a decimal, divide by 100 to move 2 decimal places to the left.

12.50% / 100 = 0.125

To convert a percentage into a fraction, rewrite the decimal number you got and put it over 1. Multiply the numerator and denominator by 1000 to move 3 decimal places to the right and get your fraction.

$\frac{0.125}{1}$ · $\frac{1000}{1000}$ = 125/1000

Divide the numerator and denominator by the GCF, 125, to get your simplified fraction.

125/125 = 1

1000/125 = 8

125/1000 = 1/8

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3 years ago

Please help me I would really appreciate it.

Karo-lina-s [1.5K]

Given:

$\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}$

To prove:

$\Delta CDA\cong \Delta ABC$

Proof:

In $\Delta CDA\text{ and } \Delta ABC$ ,

$\overline{AB}\cong \overline {CD}$ because Given

$\overline{BC}\cong \overline {DA}$ because Given

$\overline{AC}\cong \overline {AC}$ because Reflexive property.

Corresponding sides of both triangles are congruent. So,

$\Delta CDA\cong \Delta ABC$ because SSS

Therefore, the required missing values are: Given, $\overline{BC}\cong \overline {DA}$ , Reflexive property , $\Delta CDA\cong \Delta ABC$ , SSS respectively.

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3 years ago

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vladimir1956 [14]

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$\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ A(2,1)\qquad C(4,7)\qquad \qquad \stackrel{\textit{ratio from A to C}}{3:2} \\\\\\ \cfrac{A\underline{B}}{\underline{B} C} = \cfrac{3}{2}\implies \cfrac{A}{C} = \cfrac{3}{2}\implies 2A=3C\implies 2(2,1)=3(4,7)\\\\[-0.35em] ~\dotfill\\\\ B=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill$

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