Identify the indicated parts of the figure below.

Mathematics

1 answer:

Dominik [7]3 years ago

5 0

Answer:

The top one is a triangle which is the back part of the shape. The bottom left one is also a triangle and the bottom right one is a rectangle

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Elis [28]

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=x(plus symbol)7

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3 years ago

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Triangle ABC has vertices A(-2,0), B(2,5), C(3, 1). The reflection of the image of triangle ABC is triangle A'B'C' with vertices

geniusboy [140]

Answer: Reflection about x-axis

Step-by-step explanation:

Given

Initially, vertices are $A(-2,0), B(2,5),C(3,1)$

After reflection they become $A(-2,0),B(2,-5),C(3,-1)$

It is clear that the x coordinate remains unchanged and the y coordinate changes its sign. It occurs when reflection is done about the x-axis.

For example, when (a,b) is reflected about the x-axis, it becomes (a,-b).

So, here reflection is being done about the x-axis.

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3 years ago

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hram777 [196]

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4 years ago

Write the slope intercept form of the equation of the line through the given points x intercept of -5 and y intercept of -1. Pls

soldier1979 [14.2K]

bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is when the graph touches the y-axis and when that happens x = 0.

$\bf \underset{x-intercept}{(\stackrel{x_1}{-5}~,~\stackrel{y_1}{0})}\qquad \underset{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{-1}{0+5}\implies -\cfrac{1}{5}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1$