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3 years ago

67= 9x + 15 30 POINTS

2 answers:

7 0

Subtract 15 from both sides of the equation
Simplify
Divide both sides of the equation by the same term
Simplify
ANSWER: x= 52/9

horsena [70]3 years ago

4 0

Answer:

52/9

Step-by-step explanation:

9x + 15 = 67

9x = 67-15

9x = 52

x = 52/9

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Suppose you're thinking about buying one of two cars. Car it will cost $17,655. Who can expect to pay an average of $1230 Per ye

Reil [10]

Answer:

9 years

Step-by-step explanation:

A= 17655 + 1230Years

B= 15900+1425years

A=B: 1755=195years

years= 1755/195

years= 9

7 0

3 years ago

Consider the following statements:

Black_prince [1.1K]

Answer:

b. I and II are both false.

Step-by-step explanation:

I. For a significance level, the two tailed hypothesis is not always accurate than the one tailed hypothesis test. The hypothesis testing is carried to find out the correctness of a claim of a population parameter. The two tail hypothesis test which used both positive and negative tails of the distribution is not always more accurate than one tailed test.

II. The process of the point estimation involves the utilization of the values of a statistic which is obtained from the sample data to obtain the best estimate of a corresponding unknown parameter in the given population.

Hence, both the statements are false.

3 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

Can you answer this for me thank you

S_A_V [24]

Make it into a simultaneous equation:

5p + 4e = 7.65
4p + 5e = 7.20

Use adding/subtracting formula

The cost of an eraser is $1.44

3 0

3 years ago

Graph each line. Give the slope-intercept form for all standard form equations.

8090 [49]

Answer:

Slope Intercept Form is y=2x.

Step-by-step explanation:

Since slope-intercept form is y=mx+b, you need to rewrite 2x-y=0 in Slope-Intercept Form.

First, you want to subtract 2x from both sides. That comes out to -y = (-2x.)

Then, multiply each term by -1. A negative times another negative is a possitive, so -y would become y, and -2x would become 2x, giving you the answer of y=2x.

4 0

2 years ago