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sukhopar [10]
3 years ago
7

67= 9x + 15 30 POINTS

Mathematics
2 answers:
Zinaida [17]3 years ago
7 0

Subtract 15 from both sides of the equation
Simplify
Divide both sides of the equation by the same term
Simplify
ANSWER: x= 52/9
horsena [70]3 years ago
4 0

Answer:

52/9

Step-by-step explanation:

9x + 15 = 67

       9x = 67-15

       9x = 52

         x = 52/9

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Solve for an angle in right triangles
bezimeni [28]

Answer:

Angle B measures 68.19 degrees. Used SOH CAH TOA method.

5 0
3 years ago
Can Anybody Solve this and send the pic of the ans! ​
Triss [41]

Answer:

solve it yourself

Step-by-step explanation:

length of ist part= 30 cm

breadth of ist part = 21 cm

area of ist part = 630 cm

diameter of 2nd part= 21 cm

area of 2nd part = ¼dπ

π= 22/7

= ¼× 21 ×22/7

=3×10.5

= 31.5cm²

total area = ist part +2nd part + 3rd part

=

8 0
3 years ago
Look at the graph of the linear function below.
valentinak56 [21]

Answer:

C

Step-by-step explanation:

y=mx+b, where x any are variables, m is the slope and b is the y-int.

Step 1: Find the y-int

y-int = 3.25 (13/4)

Step 2: Find the slope using RISE/RUN

-13/7

Answer is C

Hope that helps

3 0
1 year ago
Read 2 more answers
Findf '(3), where f(t) = u(t) · v(t), u(3) =1, 2, −2, u'(3) =8, 1, 4,andv(t) =t, t2, t3.
Reika [66]

Answer:

f'(3)=100

Step-by-step explanation:

Given:

f(t)=u(t)\cdot v(t)\\u(3)=\left ( 1,2,-2 \right )\\u'\left ( 3 \right )=\left ( 8,1,4 \right )\\v(t)=\left ( t,t^{2},t^{3} \right )

To find: f'(3)

Solution:

v(t)=\left ( t,t^{2},t^{3} \right )

At t=3;

v(3)=(3,3^{2},3^{3} )=(3,9,27)

Differentiate with respect to t

v'(t)=\left ( 1,2t,3t^{2} \right )

At t=3;

v'(3)=\left ( 1,2(3),3(3)^{2} \right )=\left ( 1,6,27 \right )

Using product rule, differentiate f(t)=u(t)\cdot v(t) with respect to t

f'(t)=u'(t)\cdot v(t)+u(t)\cdot v'(t)

At t=3;

f'(3)=u'(3)\cdot v(3)+u(3)\cdot v'(3)\\=\left ( 8,1,4 \right )\cdot \left ( 3,9,27 \right )+\left ( 1,2,-2 \right )\cdot \left ( 1,6,27 \right )\\=24+9+108+1+12-54\\=100

7 0
4 years ago
If △ABC ≅ △DEF, then what corresponding side is congruent to side BA? (Enter answer using segment letters only.)
sdas [7]
<h3>Answer is   ED</h3>

note: ED is the same as DE. The order of the segment letters does not matter.

============================================

Explanation:

In the sequence ABC, the letter B is the second letter and A is the first.

So the corresponding segment to BA will have its first slot be the second letter of DEF, and its second slot be the first letter of DEF. That's how I'm getting ED for the answer. It is the same as DE because it's the same segment.

The corresponding sides are congruent due to the CPCTC which stands for "corresponding parts of congruent triangles are congruent".

3 0
3 years ago
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