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Lynna [10]
3 years ago
5

Round answers to three decimal places.

Mathematics
2 answers:
melamori03 [73]3 years ago
8 0

Answer:

Rounding the given answers to three decimal places

The Area of 1st rectangle ≈ 0.032

Area of 2nd rectangle =25 x 0.000863  ≈ 0.022

The Area of 3rd rectangle ≈ 0.014

The Area of 4th rectangle ≈ 0.008

The Area of 5th rectangle ≈ 0.004

The Area of 6th rectangle ≈ 0.002

Hence The Total area ≈ 0.082 ​

Step-by-step explanation:

Rounding the given answers to three decimal places

The Area of 1st rectangle ≈ 0.032

Area of 2nd rectangle =25 x 0.000863  ≈ 0.022

The Area of 3rd rectangle ≈ 0.014

The Area of 4th rectangle ≈ 0.008

The Area of 5th rectangle ≈ 0.004

The Area of 6th rectangle ≈ 0.002

Hence The Total area ≈ 0.082 ​

Darina [25.2K]3 years ago
8 0

Answer:

Rounding the given answers to three decimal places

The Area of 1st rectangle ≈ 0.032

Area of 2nd rectangle =25 x 0.000863  ≈ 0.022

The Area of 3rd rectangle ≈ 0.014

The Area of 4th rectangle ≈ 0.008

The Area of 5th rectangle ≈ 0.004

The Area of 6th rectangle ≈ 0.002

Hence The Total area ≈ 0.082 ​

Step-by-step explanation:

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The length of a rectangular building is 4 feet more than 3 times the width. The perimeter is 84 feet. Find the width and length
Rus_ich [418]

Answer:

Width=9.5, Length=32.5

Step-by-step explanation:

Let x be the width of the rectangle,

The length is 4 feet more than 3 times the width,

The length= 3x+4

The perimeter is

2(x)+2(3x+4)=84

2x+6x+8=84

8x=76

x=76/8

x=9.5

The Width=9.5

Length= 3(9.5)+4=32.5

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Y=-3x+5<br> 5x-4=-3<br> solve for x and y
IRISSAK [1]

Answer:

y = 4.4

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Step-by-step explanation:

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3 0
3 years ago
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What is the solution, if any, to the inequality 3-14-n1 &gt; 1?
mezya [45]

Answer:

n > 2 or n < 6

Step-by-step explanation:

3 - | 4 - n | < 1

Let's move 3 to the other side of the equation:

- | 4 - n | < 1 - 3

- | 4 - n | < -2

Both sides of the equation are negative, so we can simplify by multiplying them with -1:

(- | 4 - n | < -2*-1

| 4 - n | < 2

We cannot get rid of the module because it's not for a single number and we dont know what n is equal to but there is a rule that we can use to remove the module:

- if | x | < a and a > 0 then -a < x < a. So if we use it we get the following:

- 2 < 4 - n < 2

These are two equations, separate and solve them separately

4 - n < 2

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n > 2 (< turns into > because we changed sign)

and

- 2 < 4 - n

4 - n > -2

-n > -2 - 4

n < 6 (we change the sign of the numbers so the equation changes too)

So after solving the two equation we get the answers

8 0
2 years ago
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