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skad [1K]
3 years ago
9

Which equation represents the line that passes through the point (4, -5) and is perpendicular to the line x + 2y = 5?

Mathematics
1 answer:
Lerok [7]3 years ago
7 0

Answer:

y = 2x - 13

Step-by-step explanation:

Equation of a line is y = mx + c, m is the gradient and c is the intercept

The line passes through points 4 and -5, x is 4 and y is -5

-5 = 4m + c

When two lines are perpendicular, the products of their gradients are equal to -1, m1 * m2 = -1

x + 2y = 5

2y = -x + 5

y = (-1/2 * x) + 5

therefore m = -1/2

m1 * m2 = -1

m * -1/2 = -1

-m = -2 , therefore m = 2

-5 = 4 * 2 + c

c = -5 - 8, which is -13

Therefore the equation for the line is

y = 2x - 13

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This may be one of those questions that could take
more paper to ask than to answer.

Line-1 goes through  (-4, 8) and  (4,6) .

Its slope is (difference in 'y') / (difference in 'x')

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Dif in 'x' = (4 - -4) = 8
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Line-2 goes through  (-1, 1)  and  (3, 5)

Its slope is (difference in 'y') / (difference in 'x')

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