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Alex787 [66]
3 years ago
8

What is the length of the missing side?​

Mathematics
1 answer:
Anna [14]3 years ago
4 0

Answer:

first one x = 26

second one x = 11.12

Step-by-step explanation:

a^2 + b^2 = c^2

24^2 + 10^2 = c^2

676 = c^2

26 = c

a^2 = c^2 - b^2

a^2 = 12^2 - 4.5^2

a^2 = 123.75

a = 11.12

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The attendance at a baseball game was 400 people. Student tickets cost $2 and adult tickets cost $3. Total sales were $1050. How
S_A_V [24]
We know the total tickets sold = 400. Let x be the number of adult tickets sold. That means 400 - x is the number of student tickets. The revenue from adult tickets will be $3 * x, which we can call 3x. The revenue from student ticks will be $2 * (400 - x), or 800 - 2x. The total revenue is $1050, so that means: 3x + (800 - 2x) = 1050. Removing the parentheses: 3x + 800 - 2x = 1050 Subtracting 800 from both sides: 3x - 2x = 250 Simplifying the left side: x = 250, which is the number of adult tickets. 400-x = student tickets = 400-250 = 150. ALWAYS check! In this case, check the revenue: 3x = 3(250) = 750 2(150) = 300 750 + 300 = 1050. Check!
5 0
3 years ago
What is 13.235 rounded to nearest hundredth
egoroff_w [7]
Answer to your question is 13.24
5 0
3 years ago
PLEASE HELP PLESD PLED​
-BARSIC- [3]

Answer:

<h2>x = 35</h2>

Step-by-step explanation:

Because the angles are vertical angles, they must be equal.

3x + 7 = 112

3x = 105

x = 35

Check

3(35) + 7 = 112

112 = 112 Correct

7 0
2 years ago
Read 2 more answers
Solve for x. -1/3(4x+2)=1/3(x+11)
sineoko [7]

Answer:

X= -13/5

Step-by-step explanation:

i hope this helps :)

6 0
2 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
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