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2 years ago

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Eber ran 3 miles. He stopped to take a break every 34 mile. How many times did Eber stop, including his final stop at the end of

his run? Use the model to help you answer this question.

1 answer:

Elodia [21]2 years ago

3 0

144 because when you divide them and simplify

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In the diagram AB is parallel to CD. What is the value of X

aivan3 [116]

Answer:

B) 120

Step-by-step explanation:

6 0

2 years ago

In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.

REY [17]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180° ....(1)

But ∠IKC ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

5 0

2 years ago

Read 2 more answers

What are the coordinates of the turning point for the function f(x) = (x - 1)3 - 3? A. (-1, -3)

Naddik [55]

ANSWER

The turning point is

$(1,-3).$

EXPLANATION

The function given to us is

$f(x) = (x - 1) ^{3} - 3$

At turning point,
$f '(x) = 0$

So we need to differentiate the given function and equate it to zero.

We using the chain rule of differentiation, we obtain,
$f '(x) =3 (x - 1) ^{2}$

We equate this to zero to obtain,

$3 (x - 1) ^{2} = 0$

We divide through by 3.

$(x - 1) ^{2} = 0$

We solve for x to get,

$x - 1 = 0$

$x = 1$

We substitute this x-value in to the function to obtain the corresponding y-value of the turning point.

$f(1) = (1- 1) ^{3} - 3$

$f(1) = 0 - 3$

$f(1) = - 3$

Therefore the turning point is

$(1,-3)$

C is the correct answer.

6 0

2 years ago

Read 2 more answers

Choose the equation that represents the graph below: (1 point) Graph of a line passing through points 0 comma 6 and 9 comma 0 y

aleksklad [387]

Answer:

Option C is correct.

Equation of a line $y=\frac{-2}{3}x+6$ passing through (0,6) and (9,0).

Explanation:

Given the two points (0, 6) and (9 ,0).

To find the equation for the given two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is,

$y-y_{1}=m(x-x_{1})$ ; where m is the slope and is given by:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

First find the slope m:

$m=\frac{0-6}{9-0} =\frac{-6}{9} =\frac{-2}{3}$

Substitute this value in equation of line:

$y-6=\frac{-2}{3} (x-0)$ or

$y-6=\frac{-2}{3} x$

⇒ $y=\frac{-2}{3}x+6$

Therefore, the equation for the given point is: $y=\frac{-2}{3}x+6$

7 0

2 years ago

7/8 + 7/8 simplify your answer?

yanalaym [24]

The answer to your question is 1.25

8 0

2 years ago

Read 2 more answers