The solutions to q² - 125 = 0 are q = ±√125.
q = -5√5
q = 5√5
Ya I’m pretty sure it’s 125
Answer:
about 8 cm
Step-by-step explanation:
The formula for the area of a regular polygon is ...
A = 1/2Pa . . . . where P is the perimeter and "a" is the apothem, the distance from the center to a side
Filling in your numbers, we have ...
20 cm^2 = (1/2)P(5 cm)
Dividing by the coefficient of P, we find ...
2×(20 cm^2)/(5 cm) = P = 8 cm
The perimeter of the pentagon is about 8 cm.
_____
<em>Comment on the problem</em>
This calculation makes use of the area formula, as apparently intended. A regular pentagon with an apothem of about 5 cm will have an area of about 90.8 cm^2. The given geometry is impossible, as the pentagon is nearly 10 cm across. It cannot have a perimeter of only 8 cm.
The first step to solve this problem is to represent
variables for the width and the length:
Let w = width of the rectangle
2w – 1 = length
of the rectangle
The formula to compute for the area of the rectangle is:
A = LW
Substituting the values and variables to the formula:
28 = w (2w – 1)
2w^2 – w = 28
2w^2 – w – 28 = 0
Solve the quadratic equation:
(2w + 7)(w – 4) = 0
w = -7/2 or w = 4
You cannot use the -7/2 because there is no negative
measurement.
W = 4 feet
L = 2(4) – 1 = 7 feet
Therefore the dimension of the rectangle is 4 feet by 7
feet.
