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Serhud [2]
3 years ago
5

Given m|n, find the value of x. PLEQSE HELP!!

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0
Ya I’m pretty sure it’s 125
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Someone please solve. I keep getting 66 but it's wrong.​
sashaice [31]

The unlabeled part of the right angle is complementary to 68 degrees, so 22 degrees. y is supplementary to 78 degrees, so 102 degrees.  z as the third angle in the small triangle is 180 less than the sum of the other two,

z = 180 - 22 - 102

Answer: 56 degrees

7 0
4 years ago
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Cual es la suma del cierto número y- 6 es -1
GarryVolchara [31]
no se ya cállate por favor
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3 years ago
consider gk located at g (0,0) and k (4,4). describe the dilation of gk by a scale factor of 2 centered at (-2,-4)
KonstantinChe [14]

Solution: The dilation of gk by a scale factor of 2 centered at (-2,-4)  is g'(2,4) and k'(10,12).

Explanation:

It is given that the scale factor is 2 and center of dilation is (-2,-4).

If the center of dilation is (a,b) with scale factor k, then the dilation of a point P(x,y) is determined by the given formula.

D(x,y)=(a+k(x-a),b+k(y-b))     .....(1)

To find the g' substitute x=0, y=0, a=-2, b=-4 and k=2 in equation (1).

g'=(-2+2(2),-4+2(4))\\g'=(2,4)

To find the k' substitute x=4, y=4, a=-2, b=-4 and k=2 in equation (1).

k'=(-2+2(4+2),-4+2(4+4))\\g'=(10,12)

Therefore, the dilation of gk by a scale factor of 2 centered at (-2,-4) is g'(2,4) and k'(10,12).

5 0
3 years ago
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I NEED HELP WITH THESE #'S [20pts❤️]
lara31 [8.8K]
Okay, this is a written proof so what you have to do is list the steps. I am going to try my best to solve this problem...

5 0
3 years ago
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A friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work
lubasha [3.4K]

Answer:

The probability that he drove the small car is 0.318.

Step-by-step explanation:

We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.

If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.

Let the Probability that he drives the small car = P(S) = \frac{1}{4} = 0.25

Probability that he drives the large car = P(L) = \frac{3}{4} = 0.75

Also, let WT = event that he is at work on time

So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7

Probability that he is at work on time given that he takes the large car = P(WT / L) = 0.5

Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)

We will use the concept of Bayes' Theorem for calculating above probability;

So,    P(S / WT)  =  \frac{P(S) \times P(WT/S)}{P(S) \times P(WT/S)+P(L) \times P(WT/L)}

                          =  \frac{0.25 \times 0.7}{0.25 \times 0.7+0.75 \times 0.5}

                          =  \frac{0.175}{0.55}

                          =  <u>0.318</u>

Hence, the required probability is 0.318.

8 0
3 years ago
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