Answer:
It passes through the point (3,4). Given that the center of the circle is the point (0,0). We know that the equation of the circle is given by : (x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.
I dont think the answer is always. Because integers are always whole numbers. Hope that helps a little?
Answer:
A = 25
Step-by-step explanation:
Base = |-2-(-7)| = |-2+7| = 5
equation of the line that includes the base
x = 6 (because it is parallel to y axis)
the height passes to the point (-4,-4) and must be perpendicular to the base
the equation of the line of the base hasn’t the slope expressed, so the line of the height has a slope equal to 0
so the equation of the line is y= -4
the point (6,-4) is where the two lines intercept and it is the point where the height hit the base
height = |-4-6| = 10
A = (base x height)/2 = (5x10)/2 = 25
Answer:
The measure of ∠G is 59°
Step-by-step explanation:
<em>When </em><em>two secants</em><em>, intersect at </em><em>a point outside a circle</em><em> then the </em><em>measure of the angle formed between them</em><em> is </em><em>one-half the positive difference of the measures of the intercepted arcs.</em>
<em></em>
In the given figure
∵ GT is a secant that intersects the circle at points H and T
∵ GE is a secant that intersects the circle at points F and E
∴ The intercepted arcs are HF and TE
∵ GT ∩ GE at G
∵ Point G is outside the circle
→ By using the rule above
∴ m∠G = 
(m arc TE - m arc HF)
∵ m arc TE = 175°
∵ m arc HF = 57°
→ Substitute them in the rule above
∵ m∠G = (175 - 57) = (118)
∴ m∠G = 59
∴ The measure of ∠G is 59°
