2 years ago

Nine times nineteen Equals to

Mathematics

2 answers:

IrinaK [193]2 years ago

6 0

Answer:

idiot use a calculator

Step-by-step explanation:

Leokris [45]2 years ago

5 0

Answer:

171

Step-by-step explanation:

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Answer:

no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

$\dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}$

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

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Answer:

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Step-by-step explanation:

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Graph #2:

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