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aliya0001 [1]
3 years ago
10

(HELP!! WILL GIVE 86 POINTS!!)

Mathematics
2 answers:
astraxan [27]3 years ago
4 0

Answer: 2(−x+y=−2)

2(−x+y=−2)

1(2x−3y=4)

Becomes:

−2x+2y=−4

2x−3y=4

Add these equations to eliminate x:

−y=0

Then solve−y=0for y:

−y=0

−y/-1 = 0/-1 (Divide both sides by -1)

y=0

Step-by-step explanation:

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

−x+y=−2

Substitute 0 for y in −x+y=−2:

−x+0=−2

−x=−2(Simplify both sides of the equation)

−x/-1 = -2/-2 (Divide both sides by -1)

x=2

Answer:

x=2 and y=0

DerKrebs [107]3 years ago
3 0

Answer: x=y+2

Step-by-step explanation:

Step 1: Add -y to both sides.

−x+y+−y=−2+−y

−x=−y−2

Step 2: Divide both sides by -1.

-x/-1 = -y - 2/-1

asnwer: x=y+2

Answer: x = 3/2y + 2

2x−3y=4

Step 1: Add 3y to both sides.

2x−3y+3y=4+3y

2x=3y+4

Step 2: Divide both sides by 2.

2x/2 = 3y + 4/2

answer: x = 3/2y + 2

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Read 2 more answers
In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?
Mrac [35]

Answer:

Cosec <F = 73/55

Step-by-step explanation:

In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?

First you must know that;

Cosecant <F = 1/sin<F

Given

∠G=90°, GF = 48, EG = 55, and FE = 73.

ED ,= hyp = 73

EG = opp = 55*side facing <F

Using DOH CAH TOA

Sin theta = opp/hyp

Sin <F= 55/73

Reciprocate both sides

1/sinF = 73/55

Cosec <F = 73/55

3 0
3 years ago
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 4 at x = −3 and a local minimum value of 0 at
Vinvika [58]
The formula is f(x) = a x ^ 3 + b x ^ 2 + c x  + d 
f '(x) = 3ax^2 + 2bx + c. 
f(- 3) = 3 ==> - 27a + 9b - 3c + d = 3 
f '(- 3) = 0 (being a most extreme) ==> 27a - 6b + c = 0. 
f(1) = 0 ==> a + b + c + d = 0 
f '(1) = 0 (being a base) ==> 3a + 2b + c = 0. 
- 
Along these lines, we have the four conditions 
- 27a + 9b - 3c + d = 3 
a + b + c + d = 0 
27a - 6b + c = 0 
3a + 2b + c = 0 
Subtracting the last two conditions yields 24a - 8b = 0 ==> b = 3a. 
Along these lines, the last condition yields 3a + 6a + c = 0 ==> c = - 9a. 
Consequently, we have from the initial two conditions: 
- 27a + 9(3a) - 3(- 9a) + d = 3 ==> 27a + d = 3 
a + 3a - 9a + d = 0 ==> d = 5a. 
Along these lines, a = 3/32 and d = 15/32. 
==> b = 9/32 and c = - 27/32. 
That is, f(x) = (1/32)(3x^3 + 9x^2 - 27x + 15).
8 0
3 years ago
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