Question

. If Henry plays both games conservatively (CC), find the probability that Henry will earn

Answer 1

Answer:

a) for 2 points,

Pa = Pww = 0

b) for 1.5 point,

Pb = Pwt + Ptw = 0 + 0 = 0

c) for 1 point

Pc = Pwl + Ptt + Plw = 0 + 0.64 + 0 = 0.64

d) for 0.5 point

Pd = Ptl + Plt = 0.16 + 0.16 = 0.32

e) for 0 point

Pe = Pll = 0.04

Step-by-step explanation:

The remaining part of the question is attached.

Given;

According to the rules of the game

Win = 1 point

Tie = 1/2 point

Lose= 0 point

If henry play the game conservatively, the probability of

Win = 0

Tie = 0.8

Lose = 0.2

Playing the game twice and conservatively, the following outcomes are possible with the corresponding points and probabilities.

ww = 2 points Pww = 0 × 0 = 0

wt = 1.5 point Pwt = 0 × 0.8 = 0

wl = 1 point Pwl = 0 × 0.2 = 0

tw = 1.5 point Ptw = 0.2 × 0 = 0

tt = 1 point Ptt = 0.8 × 0.8 = 0.64

tl = 0.5 point Ptl = 0.8 × 0.2 = 0.16

lw = 1 point Plw = 0.2 × 0 = 0

lt = 0.5 point Plt = 0.2 × 0.8 = 0.16

ll = 0 point Pll = 0.2 × 0.2 = 0.04

Where w = win , t = tie and l = lose.

a) for 2 points,

Pa = Pww = 0

b) for 1.5 point,

Pb = Pwt + Ptw = 0 + 0 = 0

c) for 1 point

Pc = Pwl + Ptt + Plw = 0 + 0.64 + 0 = 0.64

d) for 0.5 point

Pd = Ptl + Plt = 0.16 + 0.16 = 0.32

e) for 0 point

Pe = Pll = 0.04

Answer 2

Answer:

a)  2/2 + 2/2 = 2

b)  2/2 + 1/2  = 3/2

c)  2/2 + 0/2  = 1

d)  0/2 + 0/2 = 0

Step-by-step explanation:

a) 2 points :  2/2 + 2/2 = 2    

            if henry wins both games than we get  probability =2

b) 1  1/2 or 3/2 :  2/2 + 1/2 = 3/2

             if henry wins one game and tie another game  we get probability =3/2

c) 1 point:  2/2 + 0/2 = 1

              if henry wins one game and loose second game, we get                                                       probability 1

d) 0 points: 0/2 + 0/2 = 0

                 if henry loose both games we get probability 0