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Travka [436]
3 years ago
7

5. If 16,700 J of work is done to shoot the human cannonball down a 3.05 m barrel, then how much force is applied to the person

to fire them out the cannon?
Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

5475.41N

Step-by-step explanation:

Work done = Force × distance

Given

Work done = 16700Joules

Distance = 3.05m

Required

Force

Substitute the given values into the formula as shown

16700 = Force × 3.05

Force = 16700/3.05

Force = 5475.41N

Hence the applied force is 5475.41N

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A polygon has vertices whose coordinates are A(1, 4), B(4, -1), C(-1, -4), and D(-4, 1). Use the midpoint formula to determine w
Alenkinab [10]

Answer:

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Step-by-step explanation:

The given vertices of the polygon are;

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Given that the vertices of the polygon in clockwise order from the top left corner are ABCD, we have the diagonals as AC and DB

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(x_m , \ y_m) = \left (\dfrac{x_1 + x_2}{2} , \ \dfrac{y_1 + y_2}{2} \right )

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(x_m , \ y_m) = The midpoint coordinates

Therefore, the midpoint of diagonal AC = \left (\dfrac{1 + (-1)}{2} , \ \dfrac{4 + (-4)}{2} \right ) = (0, 0)

The midpoint  of diagonal DB = \left (\dfrac{(-4) +4}{2} , \ \dfrac{1 + (-1)}{2} \right ) = (0, 0)

Therefore, given that the coordinates of the location of the midpoint of the diagonals AC and DB is the same, the diagonals bisect each other

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3 0
3 years ago
The half-life of a radioactive kind of neodymium is 11 days. If you start with 2,616 grams of it, how much will be left after 22
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Answer:

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