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stepan [7]
3 years ago
9

What is potential and kinetic energy

Physics
1 answer:
Galina-37 [17]3 years ago
3 0
<h2><u>Explanation:</u></h2>

______________________________

<u />

<h3>Potential:</h3>
  • This refers to an object having energy running through it, but being stored. It hasn't quite been released yet.
  • Ex: <em>Someone waiting to dive into a pool, when a whistle blows.</em>
<h3 /><h3>Kinetic: </h3>
  • This refers to the energy going through an object but that energy is moving, it's been released.
  • Ex: <em>A boy pedaling his bike atop a hill. </em>

______________________________

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3 years ago
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A 70 kg student now sits in the chair and the same 35 N force is applied to the chair. What is the chair's new acceleration?
amid [387]

Answer:

0.5 m/s²

Explanation:

Applying,

F = ma............... Equation 1

Where F = Force applied to the chair, m = mass of the student, a = acceleration of the chair

make a the subject of the equation

a = F/m............ Equation 2

From the question,

Given: F = 35 N, m = 70 kg

Substitute these values into equation 2

a = 35/70

a = 0.5 m/s²

Hence the new acceleration of the chair is 0.5 m/s²

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3 years ago
What is the power of a 12 V, 50 A light?
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Answer:

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3 years ago
Suppose that the average U.S. household uses 15600 kWh (kilowatt‑hours) of energy in a year. If the average rate of energy consu
sweet [91]

Answer:

a) 166.4 s

b) (2.155 × 10⁷) s

Explanation:

15600 KWh for a year,

1 year consists of 365 × 24 hours = 8760 hours.

So, the power consumed in a year for an average household = (Energy/time)

= (15600/8760) = 1.781 KW = 1781 W

a) If the average rate of energy consumed by the house was instead diverted to lift a 1.80 × 10 3 kg car 16.8 m into the air, how long would it take

The power required for this lifting = (mgh/t)

m = 1800 kg

g = 9.8 m/s²

h = 16.8 m

t = ?

P = 1781 W

1781 = (1800×9.8×16.8)/t

t = (296,352/1781)

t = 166.4 s

b) how long would it take to lift a loaded Boeing 747 airplane, with a mass of 4.05 × 10 5 kg , to a cruising altitude of 9.67 km

The power required for this lifting = (mgh/t)

m = 405000 kg

g = 9.8 m/s²

h = 9.67 km = 9670 m

t = ?

P = 1781 W

1781 = (405000×9.8×9670)/t

t = (38,380,230,000/1781)

t = 21,549,820 s = (2.155 × 10⁷) s

Hope this Helps!!!

8 0
3 years ago
The air speed of a plane is defined as its velocity with respect to the surrounding air, or in other words how fast the plane wo
amid [387]

Answer:

3

Explanation:

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