<u>Answer </u><u>:</u><u>-</u>
The person who is exerting 55N will move the box 20N to the right (<u>option B</u>).
<u>Reason :-</u>
- The total force by the two people in the left side is .. 17 N + 16N = 33N.
- So, the net force acting on the box is, 55N - 33N = <u>20N</u>.
- The box will move towards the <u>right</u> because greater force is acting there.
<em>Check </em><em>the </em><em>attached</em><em> </em><em>pictures.</em>
The statement '<span>The more particles a substance has at a given temperature, the more thermal energy it has' is true. </span><span>The
kinetic molecular theory of gases has three main laws and one of them is the
average kinetic energy of the particles in a gas. The average kinetic energy of
the gas particles is the behavior and movement it does in the surroundings. It
is directly proportional to temperature wherein if you increase the
temperature, the kinetic energy of a particle also increases. It will also
decrease its movement or its kinetic energy if the temperature lowers. </span>
Answer:
The gate will open if the height of water is equal to or more than 0.337m.
Explanation:
From the diagram attached, (as seen from the reference question found on google)
The forces are given as
Force on OA
Here
- ρ is the density of water.
- g is the gravitational acceleration constant
is the equivalent height given as
is the area of the OA part of the door which is calculated as follows:
The Force is given as
![F_1=0.6\rho g[h+0.3]](https://tex.z-dn.net/?f=F_1%3D0.6%5Crho%20g%5Bh%2B0.3%5D)
Force on OB
Here
- ρ is the density of water.
- g is the gravitational acceleration constant
- is the equivalent height given as
- is the area of the OB part of the door which is calculated as follows:
The Force is given as
![F_2=0.4\rho g[h+0.8]](https://tex.z-dn.net/?f=F_2%3D0.4%5Crho%20g%5Bh%2B0.8%5D)
Now the moment arms are given as
![\bar{y}_a=\bar{h}+\frac{I}{A\bar{h}}\\\bar{y}_a=h+0.3+\frac{\frac{1}{12}\times 0.6^3 \times 1}{0.6 \times[h+0.3]}\\\bar{y}_a=h+0.3+\frac{0.03}{h+0.3}](https://tex.z-dn.net/?f=%5Cbar%7By%7D_a%3D%5Cbar%7Bh%7D%2B%5Cfrac%7BI%7D%7BA%5Cbar%7Bh%7D%7D%5C%5C%5Cbar%7By%7D_a%3Dh%2B0.3%2B%5Cfrac%7B%5Cfrac%7B1%7D%7B12%7D%5Ctimes%200.6%5E3%20%5Ctimes%201%7D%7B0.6%20%5Ctimes%5Bh%2B0.3%5D%7D%5C%5C%5Cbar%7By%7D_a%3Dh%2B0.3%2B%5Cfrac%7B0.03%7D%7Bh%2B0.3%7D)
![\bar{y}_b=\bar{h}+\frac{I}{A\bar{h}}\\\bar{y}_b=h+0.8+\frac{\frac{1}{12}\times 0.4^3 \times 1}{0.4 \times[h+0.8]}\\\bar{y}_b=h+0.8+\frac{0.0133}{h+0.8}](https://tex.z-dn.net/?f=%5Cbar%7By%7D_b%3D%5Cbar%7Bh%7D%2B%5Cfrac%7BI%7D%7BA%5Cbar%7Bh%7D%7D%5C%5C%5Cbar%7By%7D_b%3Dh%2B0.8%2B%5Cfrac%7B%5Cfrac%7B1%7D%7B12%7D%5Ctimes%200.4%5E3%20%5Ctimes%201%7D%7B0.4%20%5Ctimes%5Bh%2B0.8%5D%7D%5C%5C%5Cbar%7By%7D_b%3Dh%2B0.8%2B%5Cfrac%7B0.0133%7D%7Bh%2B0.8%7D)
Taking moment about the point O as zero
=0.4\rho g[h+0.8](0.2+\frac{0.0133}{h+0.8})\\0.6[h+0.3](0.3-\frac{0.03}{h+0.3})=0.4[h+0.8](0.2+\frac{0.0133}{h+0.8})\\0.18h -0.054-0.018=0.08h+0.064+0.00533\\h=0.337 m](https://tex.z-dn.net/?f=F_1%28h%2B0.6-%5Cbar%7By%7D_a%29%3DF_2%28%5Cbar%7By%7D_b-h%2B0.6%29%5C%5CF_1%28h%2B0.6-h-0.3-%5Cfrac%7B0.03%7D%7Bh%2B0.3%7D%29%3DF_2%28h%2B0.8%2B%5Cfrac%7B0.0133%7D%7Bh%2B0.8%7D-h-0.6%29%5C%5CF_1%280.3-%5Cfrac%7B0.03%7D%7Bh%2B0.3%7D%29%3DF_2%280.2%2B%5Cfrac%7B0.0133%7D%7Bh%2B0.8%7D%29%5C%5C0.6%5Crho%20g%5Bh%2B0.3%5D%280.3-%5Cfrac%7B0.03%7D%7Bh%2B0.3%7D%29%3D0.4%5Crho%20g%5Bh%2B0.8%5D%280.2%2B%5Cfrac%7B0.0133%7D%7Bh%2B0.8%7D%29%5C%5C0.6%5Bh%2B0.3%5D%280.3-%5Cfrac%7B0.03%7D%7Bh%2B0.3%7D%29%3D0.4%5Bh%2B0.8%5D%280.2%2B%5Cfrac%7B0.0133%7D%7Bh%2B0.8%7D%29%5C%5C0.18h%20-0.054-0.018%3D0.08h%2B0.064%2B0.00533%5C%5Ch%3D0.337%20m)
So the gate will open if the height of water is equal to or more than 0.337m.
Answer:
Cats most commonly contract worms after coming into contact with parasite eggs or infected feces. A cat may walk through an area with eggs or infected feces, and since cats are often such fastidious groomers, they will then ingest the eggs or fecal particles as they clean their fur and feet.
Explanation:
this is the only thing in my book hope it helps
