All categories

3 years ago

Find x if...... (look at the picture and answer please)

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

5 0

Answer:

X=7

Step-by-step explanation:

108=10x+2+4x+8

108=14x+10

108-10=14x

98=14x

Divide by 14

X=7

You might be interested in

What is 100000*26748

galben [10]

Answer:

2674800000

Step-by-step explanation:

calculator

8 0

3 years ago

Read 2 more answers

Use the graph to determine the function's domain and range. Explain your answer.

mixas84 [53]

The domain is defined as all the possible x values. The graph extends to the left and to the right without bounds so the domain is All Real Values of x.
It can also be written as (-∞, ∞) This is called interval notation.

Note that the minimum value of f(x) is -4 so the range is [-4, ∞). (All real values of y equal to or greater than -4)

3 0

3 years ago

Josephine decided to get this Platinum card since she saw the ads touting the "0% A.P.R. Platinum. Sign Up

agasfer [191]

Answer: A. Her A.P.R will change after six months and be between 15.24% to 23.24% assuming that she has been making on-time payments during those first six months.

Step-by-step explanation:

8 0

3 years ago

Which set of data is correct for the quadratic relation f(x) = 5(x -

Burka [1]

Answer:

Direction parabola opens upward.

Vertex of parabola is (27,-9).

Axis of symmetry is $x=27$ .

Step-by-step explanation:

Note: Option sets are not correct.

The vertex form of a parabola is

$y=a(x-h)^2+k$ ...(1)

where, (h,k) is vertex and x=h is the axis of symmetry.

If a<0, then parabola opens downward and if a>0, then parabola opens upward.

The given function is

$f(x)=5(x-27)^2-9$ ...(2)

On comparing (1) and (2), we get

$a=5>0$ , so direction parabola opens upward.

$h=27,k=-9$ , so vertex of parabola is (27,-9).

So, axis of symmetry is $x=27$ .

6 0

3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago