Imagine we drew a line from the centre (2,0) to the point (0,4).
Essentially the line<u> we drew from the centre to that point on the circle is perpendicular to the tangent line slope-wise</u>.
The <u>slope of that line from the centre to the point is -2</u> based on the slope's equation or formula.
slope = 
Therefore the <u>tangent equation's slope is 1/2</u> since any perpendicular line's slope is the negative reciprocal of the original line's slope.
By<u> using the point-slope form, we must have the point on the tangent plane (0,4) and the slope we found which is 1/2</u>.
Hope that helps!
Answer:
x≤ −2/3y + −1/3
Step-by-step explanation:
because...
Step 1: Add -4y to both sides.
6x + 4y + −4y ≤ −2+−4y
6x ≤ −4y −2
Step 2: Divide both sides by 6.
6x/6 ≤ 
x ≤ −2/3y + −1/3
Therefor, the answer is x≤ −2/3y + −1/3
* Hopefully this helps:) Mark me the brainliest:)!!
Answer:
The answer is 27
Step-by-step explanation:
I worked it out using a calculator
Answer:
in my opinion it is polynomial function
Answer:
a = √11 and b = 6
Step-by-step explanation:
Refer to attached picture for reference
for an right triangle with angle θ
we are given
cos θ = 5/6 = length of adjacent side / length of hypotenuse
hence
adjacent length = 5 units
hypotenuse length = 6 units
the missing side is the "opposite" length which we can find with the Pythagorean equation. in our case:
hypotenuse ² = adjacent ² + opposite² (rearrange)
opposite ² = hypotenuse ² - adjacent ²
opposite ² = 6² - 5²
opposite = √ (6²-5²) = √11
sin θ = opposite length / hypotenuse (substitute values above)
sin θ = √11 / 6
hence a = √11 and b = 6
