3 years ago

Prove that the sum of three consecutive integers is divisible by 3

Mathematics

2 answers:

nadya68 [22]3 years ago

6 0

Since n (any number) + (n+1) + (n+2) is also 3n + 3, it must be divisible by 3 because it is multiple of 3

11111nata11111 [884]3 years ago

4 0

Answer:

n+n+1+n+2=3n+3=3(n+1)

Step-by-step explanation:

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Zigmanuir [339]

Answer:

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3 years ago

Select the function that's represented in the graph. Question 5 options: A) ƒ(x) = x2 – 3 B) ƒ(x) = –1∕2x2 – 3 C) ƒ(x) = –x2 – 3

Neporo4naja [7]

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hello,

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