Answer:
The system will shift to the right (Forward).
Explanation:
Based on the equilibrium:
2CO(g) + O2(g) ⇄ 2CO2(g)
If the amount of O2 is increased: The equilibrium will shift to the right trying to decrease this concentration following the Le-Ch principle that says:
A change in an equilibrium will be counteracted by the system producing a response that restore the initial state.
Answer:
The empirical formula of the compound C₃H₆N₂ is C₃H₆N₂
Explanation:
The empirical formula of a compound is the formula of the compound given in the (smallest) whole number ratio of the elements of the compound
The empirical formula of S₂O₂ is SO
The empirical formula of C₃H₆O₃ is CH₂O
The given compound's molecular formula is C₃H₆N₂
The smallest whole number ratio of of the elements of the compound is 3:6:2, therefore, the empirical formula of the compound C₃H₆N₂ is C₃H₆N₂.
Answer:
330.95K
Explanation:
V₁ = 1.2L
T₁ = 25°C = (25 + 273.15)K = 298.15K
P₁ = 1.0 atm
P₂ = 0.74 atm
V₂ = 1.8L
T₂ =?
From combined gas equation,
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Solve for T₂
T₂ = (P₂ * V₂ * T₁) / (P₁ * V₁)
T₂ = (0.74 * 1.8 * 298.15) / (1.0 * 1.2)
T₂ = 397.1358 / 1.2
T₂ = 330.9465K
T₂ = 330.95K or T₂ = (330.95 - 273.15)°C = 57.8°C
Answer:
pKa = 4.89.
Explanation:
We can solve this problem by using the <em>Henderson-Hasselbach equation</em>, which states:
pH = pKa + log
In this case [A⁻] is the concentration of sodium benzoate and [HA] is the concentration of benzoic acid.
We <u>input the given data</u>:
4.63 = pKa + log
And <u>solve for pKa</u>:
pKa = 4.89
Answer:
See explanation and image attached
Explanation:
We know that some substituted benzene reacts faster than benzene towards electrophillic substitution. This is often due to the activation of the benzene ring towards electrophillic substitution by resonance.
-OCH3 directs an incoming electrophile (such as during bromination) to the ortho or para position. This is made possible by resonance (mesomeric) effect as shown in the image attached to this answer.
Image credit: pinterest