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Fed [463]
3 years ago
14

Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equatio

n is balanced.
HCLO44 + KOH -->
Chemistry
1 answer:
butalik [34]3 years ago
6 0

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.

A balanced chemical equation always follows this law.

For the given chemical reaction, the balanced equation follows:

HClO_4+KOH\rightarrow KClO_4+H_2O

This is considered as neutralization reaction because an acid reacts with a base to produce a salt and water.

Hence, the balanced chemical equation is written above.

You might be interested in
385 J of heat are needed to heat a piece of aluminum from 22°C to 45°C. If the specific heat of Al is 0.90 J/g°C, what is the ma
VikaD [51]

Answer:

M of Al=33.09g or 0.0331kg

Explanation:

Heat Energy= specific heat*mass*change in temperature

H=M*C*T

make M subject of the formula

M=H/CT

M=685J/0.90J/g°C*(45°C-22°C)

M=685J/0.90J/g°C*23°C

M=685J/20.7J/g

M=33.09g or 0.0331kg

4 0
3 years ago
How many molecular of H2O and O2 are present in 8.5g of H2O2 ?​
Mama L [17]

2H2O+O2--->2H2O2  

8.5 gm H2O2=0.25 mole  

hence H2O is also 0.25 mole i.e.4.5 gm  

O2is 0.125 mole i.e.4 gm

4 0
3 years ago
Help fast please it's timed ​
lys-0071 [83]

Answer: B its most likely

6 0
3 years ago
Read 2 more answers
If a radioactive isotope has a half-life of 26.5 days, how many days does it take for a sample of the isotope to decrease by 35.
dangina [55]

Answer:

16.5 days

Explanation:

Given that:

Half life = 26.5 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{26.5}\ days^{-1}

The rate constant, k = 0.02616 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

35.0 % is decomposed which means that 0.35 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 1 - 0.35 = 0.65

t = 7.8 min

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.65=e^{-0.02616\times t}

<u>t = 16.5 days.</u>

7 0
3 years ago
Calculate the number of kilojoules of energy required to convert 50.0 grams of solid DMSO initially at a temperature of 19.0°C t
GuDViN [60]

Answer:

20.79 kilojoules

Explanation:

Using Q = m×c×∆T

Where;

Q = Quantity of heat (J)

c = specific heat capacity of solid DMSO (1.80 J/g°C)

m = mass of DMSO

∆T = change in temperature

According to the provided information, m= 50g, initial temperature = 19.0°C, final temperature= 250.0°C

Q = m×c×∆T

Q = 50 × 1.80 × (250°C - 19°C)

Q = 90 × 231

Q = 20790 Joules

To convert Joules to kilojoules, we divide by 1000 i.e.

20790/1000

= 20.79 kilojoules

Hence, 20.79 kilojoules of energy is required to convert 50.0 grams of solid DMSO to gas.

4 0
3 years ago
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