Answer:
(a) -49.9 kJ/mol;
(b) To the right;
(c) 34.6 kJ/mol
Explanation:
(a) For this reaction, since it's at equilibrium and standard states, we know that we can apply the equation:

Substituting the given variables:

(b) Notice that this reaction is spontaneous, since
. This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.
(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:
![Q_f = \frac{[Ni(NH_3)_6]^{2+}}{[Ni^{2+}][NH_3]^6} = \frac{0.010}{0.0010\cdot 0.0050^6} = 6.4\cdot 10^{14}](https://tex.z-dn.net/?f=Q_f%20%3D%20%5Cfrac%7B%5BNi%28NH_3%29_6%5D%5E%7B2%2B%7D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5BNH_3%5D%5E6%7D%20%3D%20%5Cfrac%7B0.010%7D%7B0.0010%5Ccdot%200.0050%5E6%7D%20%3D%206.4%5Ccdot%2010%5E%7B14%7D)
Now, notice that
. In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.
Calculate:

Answer:
a. absorbs energy as heat and has positive enthalpy of solution.
Explanation:
A reaction can either be exothermic or endothermic. An endothermic reaction, as the dissolution described in the question, is that which absorbs heat energy from the surroundings in order to start the reaction.
Because an endothermic reaction makes heat lost from the surroundings, the enthalpy (∆H) of the solution will be positive (+). ∆H is got by finding the difference between the enthalpy of the reactants and products and since the enthalpy of a product in endothermic reaction is more, the enthalpy change (∆T) will be positive.
The answer is D I believe