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lawyer [7]
3 years ago
6

Use three different values of n to demonstrate that 2n + 3n is equivalent to 5n.

Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0
 n can be 0 so 2(0) +3(0) = 0 now lets go up by one so 2(1) +3(1)= 5 now we will go up another number so lets go for 2(2)= 10 so  we figured out that 2(1) +3(1) is  5 so n equals 1

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1 yd = 36 inches

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8(36) = 288
so in 8 yd we have 288 inches
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2 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

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A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

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s=\frac{5+5+4}{2}=\frac{14}{2}=7

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Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

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3 years ago
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kakasveta [241]

Answer:

Step-by-step explanation:

3(a+3)-6=21

<=>3a+9-6=21

<=>3a+3=21

<=>3a=18

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x = -4

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