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3 years ago

HELP ASAP!!

Mathematics

1 answer:

olga2289 [7]3 years ago

8 0

Answer:

62.5%

Step-by-step explanation:

150/240=0.625

you do 0.625x100 to get the percent.

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Fill in the box with the appropriate measure.<br> quick please I have only a few min left

Art [367]

Step-by-step explanation:

first box on the left

r=4

d=8

circumference= 2π*4= 8π

area = π*4*4= 16π

Second box on the left

d=6

r= 3

circumference= 2π*3= 6π

area =π*3*3= 9π

third box on the left

A=36π

A=36πarea= π*r*r

A=36πarea= π*r*rr= 6

A=36πarea= π*r*rr= 6d=12

A=36πarea= π*r*rr= 6d=12circumference= 2π*6= 12 π

the last box

C=18π

C=18πC= 2π*r

C=18πC= 2π*rr= 9

C=18πC= 2π*rr= 9d=18

C=18πC= 2π*rr= 9d=18area= π*9*9= 81π

8 0

3 years ago

Which graph shows exponential growth?

gtnhenbr [62]

Answer:

The second graph.

Step-by-step explanation:

The one where the line is curving upwards.

5 0

3 years ago

Read 2 more answers

What is a woman and a boy no clothes going at each other called? go full detail

Harlamova29_29 [7]

Answer:

sex i guess

Step-by-step explanation:

plzzz mark bianlist

8 0

3 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .