Is there a b ok but it’s A
Answer:
I am pretty sure the answer would be B!
Hope this helps
Mark me brainliest if I'm right :)
Answer:
They should insert that y value into the other equation.
Step-by-step explanation:
Answer:
D. 18.68
Step-by-step explanation:

Applying PEMDAS as order of operations.
Solving the exponents first ![[(\frac{2}{5})^2=\frac{4}{25}]](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B2%7D%7B5%7D%29%5E2%3D%5Cfrac%7B4%7D%7B25%7D%5D)

Multiplying ![[53\times \frac{4}{25}=8.48]](https://tex.z-dn.net/?f=%5B53%5Ctimes%20%5Cfrac%7B4%7D%7B25%7D%3D8.48%5D)

Dividing ![[27\div \frac{5}{3}=16.2]](https://tex.z-dn.net/?f=%5B27%5Cdiv%20%5Cfrac%7B5%7D%7B3%7D%3D16.2%5D)

Adding and subtracting.

Answer:
The function y = sec(x) shifted 3 units left and 7 units down .
Step-by-step explanation:
Given the function: y = sec(x)
- If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.
- If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.
The function
comes from the base function y= sec(x).
Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.
Therefore, the transformation on the given function is shifted 3 units left and 7 units down