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Snezhnost [94]
1 year ago
14

The product of 10 and a number is 3 less than the number.

Mathematics
1 answer:
djverab [1.8K]1 year ago
5 0

Answer:

-1/3

Step-by-step explanation:

The product of 10 and a number is 3 less than the number.

Ok, lets call this number x.

10x = x-3 is how to algebraically write this out.

now, lets subtract x from both sides

9x = -3

Divide by 9

x = -1/3

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Answer:

10100=15700(1-0.075)^x

10100=15700(0.925)^x

divide both sides by 15700

0.925^x=101/157

convert decimal

(37/40)^x=101/157

take the log

x= log 37/40 (101/157)

x= 5.65824

7 0
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Cathy cut 2 apples into 6 slices each she ate 9 slices which expresion matches the words
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The polynomial 8x2 – 8x + 2 – 5 + x is simplified to 8x2 – gx – h. What are the value of g and h?
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Please i need some help on this question
Pachacha [2.7K]

Answer:

1) For 3 tickets, the cost is $12

2) For 5 tickets, the cost is $20

3) $28 can purchase 7 tickets

4) For 10 tickets, the cost is $40

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1) For 3 tickets

8 = 2

x = 3

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2x = 8 x 3

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Use the same principle for the other questions. Use X (or any other variable) to represent the missing value, I e. the value you are calculating.

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7 0
2 years ago
In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0
2 years ago
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