The first one is greater. Adding 3.2 and 0.2 is easy! It's 3.4! Make that 3. Make 6.9, 7. 7×3=21. For the first one, make 1.9, 2. Then Make 3.15, 3. 5×5=25. That is why the first one is greater.
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
8/15
Step-by-step explanation:
Well to add fractions you have to have the same denominator so you would multiply your 1/3 by 5 to be 5/15 then you can add.
3/15 + 5/15 = 8/15
