Answer:
In order to do so, we need to use basic algebra. The angles in a kite add up to 360 degrees. so we form the following equation.
x + y + y + 16 = 360
x + y + y = 344 <----(360 -16)
Each letter or variable represents an angle measure. the measures of the three angles left. The 16 degrees is on the bottom of the kite and the angle opposite is the top angle. the two side angles will be the same measure that's why they are both y.
x + 2y = 344
The two side angles will be 90 or greater because there is only 1 acute angle. 90 is the smallest number that can be chosen. so we do the following.
Step-by-step explanation:
x + 2(90) = 344
x + 180 = 344
x = 344-180
x = 164
THE MAXIMUM WHOLE NUMBER MEASURE OF THE ANGLE OPPOSITE OF THE 16 DEGREE ACUTE ANGLE IS 164 DEGREES*
Answer:
R3 <= 0.083
Step-by-step explanation:
f(x)=xlnx,
The derivatives are as follows:
f'(x)=1+lnx,
f"(x)=1/x,
f"'(x)=-1/x²
f^(4)(x)=2/x³
Simialrly;
f(1) = 0,
f'(1) = 1,
f"(1) = 1,
f"'(1) = -1,
f^(4)(1) = 2
As such;
T1 = f(1) + f'(1)(x-1)
T1 = 0+1(x-1)
T1 = x - 1
T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2
T2 = 0+1(x-1)+1(x-1)^2
T2 = x-1+(x²-2x+1)/2
T2 = x²/2 - 1/2
T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3
T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3
T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)
Thus, T1(2) = 2 - 1
T1(2) = 1
T2 (2) = 2²/2 - 1/2
T2 (2) = 3/2
T2 (2) = 1.5
T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)
T3(2) = 4/3
T3(2) = 1.333
Since;
f(2) = 2 × ln(2)
f(2) = 2×0.693147 =
f(2) = 1.386294
Since;
f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).
Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,
Since;
f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2
Finally;
R3 <= |2/(4!)(2-1)^4|
R3 <= | 2 / 24× 1 |
R3 <= 1/12
R3 <= 0.083
A,B,E
C in case y=1, im not entierly sure what is implied by identity unless youre talking composition or inverses
Factors of 38
1, 2, 19, 38
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1×38
2×19
Factors of 59
1, 59
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Common factors for 38 and 59
1 is the only common factor
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GCF of 38 and 59
1 is the both the common and GCF of 38 and 59
