Answer:
(a)77.4bpm
(b)Mean of Sample 1 = 70.3 beats per minute.
Mean pulse of sample 2 = 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.
Step-by-step explanation:
(a)Population mean pulse.
The pulse of the nine students which represent the population are:
- Perpectual Bempah 64
- Megan Brooks 77
- Jeff Honeycutt 89
- Clarice Jefferson 69
- Crystal Kurtenbach 89
- Janette Lantka 65
- Kevin McCarthy 88
- Tammy Ohm 69
- Kathy Wojdya 87
The population mean pulse is approximately 77.4 beats per minute.
(b)Sample 1: {Janette,Clarice,Megan}
- Janette: 65bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 1
Sample 2: {Janette,Clarice,Megan}
- Perpetual: 64bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 2
The mean pulse of sample 1 is approximately 70.3 beats per minute.
The mean pulse of sample 2 is approximately 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.
solution:
Consider the differential equation,
7ty + (1+t2)1/2y1 = 0
Rewrite the DE as,
(1+t2)1/2dy = - 7ty
dy/y = -7t/√1+t2 dt
in y = -7(1+t2) + c
y = ce-7(1+t2)
given,
y(0) = 1 => ce-7 = -1 => c = e7
ᴪ (t,y) = y -ce ᴪ(0,1)(1+t2)
Answer:
Correct answer: g(x) = 2x - 11
Step-by-step explanation:
y= 0 => x = 5/2 => x + 3 = 5/2 + 3 = 5/2 + 6/2 = 11/2 => y = 2x - 11
God is with you!!!
4^3
you can write it like 4 × 4 × 4
you can also call it "Four to the Third power". or "Four cubed".
Answer:
(2,1)
Step-by-step explanation:
The solution is the point where the two lines cross.
Hope this helped! :)