a. What percent of people earn less than $40000?
Solution: Let S be the random variable of a salary of employee (in $), S ~ N(50000,20000). Then the random
variable X =−50000
20000
~N(0,1).
( < 40000) = ( <
40000 − 50000
20000 ) = ( < −0.5) = (−0.5) = 0.3085375.
Here Φ(x) denotes the cumulative distribution function of a standard normal distribution.
Answer: 31%.
b. What percent of people earn between $45000 and $65000?
Solution:
(45000 < < 65000) = (
45000 − 50000
20000 < <
65000 − 50000
20000 ) = (−0.25 < < 0.75)
= (0.75) − (−0.25) = 0.7733726 − 0.4012937 = 0.3720789.
Answer: 37%.
c. What percent of people earn more than $70000?
Solution:
( > 70000) = ( >
70000 − 50000
20000 ) = ( > 1) = 0.8413447.
Answer: 84%.
Answer:
The answer would be 17
Step-by-step explanation:
The answer would be 17 because if you add 12 plus 5 That would be your answer
Answer:
y + x = 7
Step-by-step explanation:
Standard form should be
y - 9 = -(x+2)
y = -x -2 +9
y + x = 7
C.,E
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Answer:
<u>If it's 18.4b=44.16:</u> 
<u>If it's 4b=44.16:</u> 
Step-by-step explanation:
<u>If it's 18.4b=44.16:</u>
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<u>If it's 4b=44.16:</u>
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