1 Expand
1.4t-0.4t+1.24=5.8
2 Simplify 1.4t-0.4t+1.241.4t−0.4t+1.24 to t+1.24t+1.24
t+1.24=5.8
3 Subtract 1.241.24 from both sides
t=5.8−1.24
4 Simplify 5.8-1.245.8−1.24 to 4.564.56
t=4.56
Each interior angle = 540/5= 108
Answer:
0.049168726 light-years
Step-by-step explanation:
The apparent brightness of a star is
where
<em>L = luminosity of the star (related to the Sun)
</em>
<em>d = distance in ly (light-years)
</em>
The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.
Hence the apparent brightness of Alpha Centauri A is
According to the inverse square law for light intensity
where
light intensity at distance
light intensity at distance
Let
be the distance we would have to place the 50-watt bulb, then replacing in the formula
Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.
Answer:
i think they are y and (x,y)