It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is ![^{41}C_1](https://tex.z-dn.net/?f=%20%5E%7B41%7DC_1%20)
Likewise, the number of ways a female student can be chosen from 48 females is
.
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
![^{41}C_1\times ^{48}C_1=1968](https://tex.z-dn.net/?f=%20%5E%7B41%7DC_1%5Ctimes%20%5E%7B48%7DC_1%3D1968%20)
Answer:
loss
Step-by-step explanation:
you might want to check someone else answer first tho
Answer:
-4/7, -1/19, 7/4
Step-by-step explanation:
The fractions converted into decimals would be -0.05, 1.75, -0.57