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Brilliant_brown [7]
3 years ago
14

Explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

Solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

Step-by-step explanation:

We need to explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.

<em>Equivalent expressions are those that have same values for any value of variable substituted.</em>

Now, We check if our expressions are equivalent, by evaluating the expression for t=2.

If they are equivalent, they would have same result after evaluation.

First, put t=2 into 14t-3t

14t-3t\\Put\:t=2\\=14(2)-3(2)\\=28-6\\=22

Now put t=2, into 3t-14t

3t-14t\\Put\:t=2\\=3(2)-14(2)\\=6-28\\=-22\\

For solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

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A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require
Aleksandr-060686 [28]

Answer:

r\approx 1.084\ feet

h\approx 1.084\ feet

\displaystyle A=11.07\ ft^2

Step-by-step explanation:

<u>Optimizing With Derivatives </u>

The procedure to optimize a function (find its maximum or minimum) consists in :

  •  Produce a function which depends on only one variable
  •  Compute the first derivative and set it equal to 0
  •  Find the values for the variable, called critical points
  •  Compute the second derivative
  •  Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 ft^3. The volume of a cylinder is given by

\displaystyle V=\pi r^2h

Equating it to 4

\displaystyle \pi r^2h=4

Let's solve for h

\displaystyle h=\frac{4}{\pi r^2}

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

\displaystyle A=\pi r^2+2\pi rh

Replacing the formula of h

\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )

Simplifying

\displaystyle A=\pi r^2+\frac{8}{r}

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

\displaystyle A'=2\pi r-\frac{8}{r^2}=0

Rearranging

\displaystyle 2\pi r=\frac{8}{r^2}

Solving for r

\displaystyle r^3=\frac{4}{\pi }

\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet

Computing h

\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

\displaystyle A''=2\pi+\frac{16}{r^3}

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.

The minimum area is

\displaystyle A=\pi(1.084)^2+\frac{8}{1.084}

\boxed{ A=11.07\ ft^2}

8 0
3 years ago
Grace rides her bike 21 km in 1 1/6 hours. What is her average speed in kilometers per hour?
aleksandrvk [35]
126 because 20 X 6 and 6 x 1
4 0
2 years ago
On a map, 2 inches represents 300 miles. How many inches would there be between two cities that are 1,200 miles apart?
solniwko [45]

Answer:

8

Step-by-step Explanation:

Step 1. Divide 1200 by 300:

1200 ÷ 300 = 4

Step 2. Multiply 4 by 2:

4 * 2 = 8

6 0
3 years ago
Can one fifth be simplified
Svetradugi [14.3K]
No, and never, cus there ain't any numbers that are greater than 1 that can go into both of them.
<span>so basically if the numerator is 1, you can't simplify it anymore. Is Impossible.</span><span />
3 0
3 years ago
When Theresa got her puppy, it weighed 6 ponds less than 2/3 of its weight now. If the puppy weighed 4 pounds when she first rec
sesenic [268]

Answer:

15 lb

Step-by-step explanation:

let the current weight of the puppy be X, the  initial weight of the puppy is 4lb or \frac{2}{3}X-6\ lb, (6 lb less 2/3 X) .

#We equate the current weight to the initial weight to determine X:

4\ lb=\frac{2}{3}X-6\ lb\\\\10 \ lb=\frac{2}{3}X\\\\X=15

Hence, the current weight of the puppy is 15 lb

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3 years ago
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