The mean absolute deviation of the ages of the ages of the people at the party is 32.70
What is the significance of the mean absolute deviation?
The mean absolute deviation measures how far each age is from the mean
The first step is to determine the mean of the data distribution
mean=(75+28+16+8+4+12+80+93+37+50)/10
mean=40.30
We need to determine the difference between each age and the mean age disregarding negative signs
sum of distances from the mean=(75-40.30)+(28-40.30)+(16-40.30)+(8-40.30)+(4-40.30)+(12-40.30)+(80-40.30)+(93-40.30)+(37-40.30)+(50-40.30)
sum of distances from the mean=34.70+12.30+24.30+32.30+36.30+28.30+39.70+52.70+56.70+9.70
sum of distances from the mean=327.00
MAD=327.00/10
MAD=32.70
On the average, each age is 32.70 years away from the mean age of 40.30
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