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Pie
3 years ago
7

Can some one please help me with this

Mathematics
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

I think the answer is B. I hoped I helped a little

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How do you do all of these
aev [14]
You just simply the answer
6 0
3 years ago
In ΔVWX, x = 78 cm, w = 35 cm and ∠W=48°. Find all possible values of ∠X, to the nearest degree.
sattari [20]

Answer:

no possible answers

Step-by-step explanation:

V

W

X

w = 35

x = 78

48°

?°

\frac{\sin A}{a}=\frac{\sin B}{b}

a

sinA

​

=

b

sinB

​

From the reference sheet (reciprocal version).

\frac{\sin X}{78}=\frac{\sin 48}{35}

78

sinX

​

=

35

sin48

​

Plug in values.

\sin X=\frac{78\sin 48}{35}\approx 1.6561513

sinX=

35

78sin48

​

≈1.6561513

Evaluate.

X=\sin^{-1}(1.6561513)= \text{ERROR}

X=sin

−1

(1.6561513)=ERROR

Sine cannot be greater than 1.

\text{No Possible Triangles}

No Possible Triangles

\{\}

{}

5 0
3 years ago
Sally wants to buy a cell phone. The price of the cell phone she had wanted had increased from $200 last week to $240 this week.
notsponge [240]
20%

200 divided by 5 equals 40
4 0
2 years ago
What is equation of a line that is parallel to y = -6x – 1 and passes through the point (1,4)
Akimi4 [234]

Answer:

y = -6x + 10

Step-by-step explanation:

Parallel lines share the same slope.  Given y = -6x – 1, we know that the equation of this new line has the form y = -6x – C.  The coordinates of the point (1, 4) determine the value of C:

(4) = -6(1) – C, or:

4 = -6 - C

Then C = -10, and the desired equation is

y = -6x – (-10), or

y = -6x + 10

5 0
3 years ago
A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

C = Children; S = Students; A = Adults

For the capacity, we have:

C + S + A = 329

For the tickets sold, we have:

5C + 7S + 12A = 2388

Half as many as adults are children implies that:

A = \frac{C}{2}

Required

Solve for A, C and S

The equations to solve are:

C + S + A = 329 -- (1)

5C + 7S + 12A = 2388 -- (2)

A = \frac{C}{2} -- (3)

Make C the subject in (3)

C = 2A

Substitute C = 2A in (1) and (2)

C + S + A = 329 -- (1)

2A + S + A = 329

3A + S = 329

Make S the subject

S = 329 - 3A

5C + 7S + 12A = 2388 -- (2)

5*2A + 7S + 12A = 2388

10A + 7S + 12A = 2388

7S + 22A = 2388

Substitute S = 329 - 3A

7(329 - 3A) + 22A = 2388

2303 - 21A + 22A = 2388

2303 +A = 2388

Solve for A

A = 2388 - 2303

A = 85

Recall that: C = 2A

C = 2 * 85

C = 170

Recall that: S = 329 - 3A

S = 329 - 3 * 85

S = 329 - 255

S = 74

Hence, the result is:

C = 170

S = 74

A = 85

8 0
3 years ago
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