Answer:
The probability that at lest one job will be missed in 57 second is
=0.819134
Step-by-step explanation:
Poisson distribution:
A discrete random variable X having the enumerable set {0,1,2,....} as the spectrum, is said to be Poisson distribution.
for x=0,1,2...
λ is the average per unit time
Given that, a job arrives at a web server with the probability 0.03.
Here λ=0.03, t=57 second.
The probability that at lest one job will be missed in 57 second is
=P(X≥1)
=1- P(X<1)
=1- P(X=0)
=0.819134
Answer:
4 I guess..........not sure but my answer is 4
Answer:
-5x^2-2x
Step-by-step explanation:
When distributing, you multiply the term outside the brackets to all the terms in brackets.
If the term outside the bracket is negative, then when distributing/opening the brackets, the signs of the terms changes.
So in this prob. -x would multiply to both +5x and +2
-x*5x+-x*2
∴-5x^2-2x
Answer:
a) 9%
, not unusual
b) 42.4%
c) 48.4%
d) 11.1%
, 44.4%
, 44.4%
Step-by-step explanation:
We have the following information from the statement:
n = 12
r = 4
a)
P (likebothofthem) = P (likefirstsong) * P (likesecondsong)
P = 4/12 * 3/11
P = 0.09 = 9%
The probability is not unusual, unusual is considered less than 0.05 or 5%
b)
P (likeneither) = P (notlikefirstsong) * P (notlikesecondsong)
P = 8/12 * 7/11
P = 0.424 = 42.4%
c) P (likeexactlyoneofthem) = P (firstsongliked) * P (secondsongnotliked) + P (firstsongnotliked) * P (secondsongliked)
P = (4/12 * 8/11) + (8/12 * 4/11)
P = 0.484 = 48.4%
d)
a)
P (likebothofthem) = P (likefirstsong) * P (likesecondsong)
P = 4/12 * 4/12
P = 0.111 = 11.1%
The probability is not unusual, unusual is considered less than 0.05 or 5%
b)
P (likeneither) = P (notlikefirstsong) * P (notlikesecondsong)
P = 8/12 * 8/12
P = 0.444 = 44.4%
c) P (likeexactlyoneofthem) = P (firstsongliked) * P (secondsongnotliked) + P (firstsongnotliked) * P (secondsongliked)
P = (4/12 * 8/12) + (8/12 * 4/12)
P = 0.444 = 44.4%
