Answer:
(0, 8).
Step-by-step explanation:
The y intercept occurs when  = 0, so we have the equation:
y = -3(0) + 8
y = 0 + 8
y = 8.
The answer is (0, 8).
 
        
             
        
        
        
Answer:
y = - 10
Step-by-step explanation:
Given that y varies directly with x then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition y = 2 when x = - 4, that is
2 = - 4k ( divide both sides by - 4 )
 = k, that is
k = -  
y = -  x ← equation of variation
When x = 20, then
y = -  × 20 = - 10
 
        
             
        
        
        
Answer:
$134,061.09
Step-by-step explanation:
hope this helps
 
        
                    
             
        
        
        
Answer:
x= 0 ,  ,
 , 
Step-by-step explanation:
Given, equation is ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D) +
 + ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D) =
 = ![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D) . →→→ (1)
. →→→ (1)
Now, by cubing the equation on both sides, we get
 ( ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D) +
 + ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D) )³ = (
 )³ = (![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D) )³
)³
⇒ (15x-1) + (13x+1) + 3×![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D) ×
×![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D) (
 (![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D) +
 + ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D) ) = 64 x.
) = 64 x.
⇒ 28x + 3×![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D) ×
×![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D) (
 (![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D) ) = 64x.
) = 64x.         
(since from (1),  ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D) +
 + ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D) =
 = ![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D) )
)
⇒ 12× ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D) ×
×![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D) (
 (![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D) )= 36x.
)= 36x.
⇒ 3x = ![\sqrt[3]{(15x-1)(13+1)(x)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2815x-1%29%2813%2B1%29%28x%29%7D) .
.
Now, once again cubing on both sides, we get
(3x)³ = (![\sqrt[3]{(15x-1)(13+1)(x)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2815x-1%29%2813%2B1%29%28x%29%7D) )³.
)³.
⇒ 27x³ = (15x-1)(13x+1)(x).
⇒ 27x³ = 195x³ + 2x² - x 
⇒ 168x³ + 2x² - x = 0
⇒ x(168x² + 2x -1) = 0
⇒ by, solving the equation we get ,
x = 0 ; x =  ; x =
 ; x = 
therefore, solution is x= 0 ,  ,
 , 
 
        
             
        
        
        
Answer:
correct option is △XYZ ~ △X'Y'Z'.
Step-by-step explanation:
since ΔXYZ is dilated by some scale factor so, the resulting triangle can not be congruent to the ΔXYZ. so option 2 is wrong.
as we have explained that the two triangles are not congruent then it's sides and angles also can't be congruent so, option 3 is also incorrect.
As we don't know by what factor the triangle XYZ is dilated so we can't say anything about correctness of option 4 and 5. 
ΔXYZ  was reflected over a vertical line and then dilated so the resulting ΔX'Y'Z' is similar to ΔXYZ.
i.e., △XYZ ~ △X'Y'Z'.