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Mamont248 [21]
3 years ago
5

I need some help and can you please show your work? Thank you have a good day

Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0

Answer:

Step-by-step explanation:(4+7)-(1)

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A line has an equation of y = - 3x + 8. What is the y-intercept of the line? Please enter your answer as a coordinate (x, y). *
mina [271]

Answer:

(0, 8).

Step-by-step explanation:

The y intercept occurs when  = 0, so we have the equation:

y = -3(0) + 8

y = 0 + 8

y = 8.

The answer is (0, 8).

6 0
3 years ago
If y varies directly with x, and y = 2 when x = −4, what is the value of y when x = 20
Klio2033 [76]

Answer:

y = - 10

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 2 when x = - 4, that is

2 = - 4k ( divide both sides by - 4 )

= k, that is

k = -  

y = -  x ← equation of variation

When x = 20, then

y = -  × 20 = - 10

3 0
3 years ago
13,406,109 pennis into dollars
geniusboy [140]

Answer:

$134,061.09

Step-by-step explanation:

hope this helps

4 0
3 years ago
Read 2 more answers
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
△XYZ was reflected over a vertical line, then dilated by a scale factor of , resulting in △X'Y'Z'. Which must be true of the two
Igoryamba

Answer:

correct option is △XYZ ~ △X'Y'Z'.

Step-by-step explanation:

since ΔXYZ is dilated by some scale factor so, the resulting triangle can not be congruent to the ΔXYZ. so option 2 is wrong.

as we have explained that the two triangles are not congruent then it's sides and angles also can't be congruent so, option 3 is also incorrect.

As we don't know by what factor the triangle XYZ is dilated so we can't say anything about correctness of option 4 and 5.

ΔXYZ  was reflected over a vertical line and then dilated so the resulting ΔX'Y'Z' is similar to ΔXYZ.

i.e., △XYZ ~ △X'Y'Z'.

5 0
3 years ago
Read 2 more answers
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