Answer:
105/330 = 21/66 = 7/22
7/22 is the answer I think
Step-by-step explanation:
n(U) = 330
n(A) = 85
n(B) = 200
n(A n B) = 60
Now,
n(A U B) = n(A) + n(B) - n(A n B)
or, n(A U B) = 85 + 200 - 60
or, n(A U B) = 285 - 60 = 225
Now,
n(A U B) compliment = n(U) - n(A U B)
n(A U B) compliment = 330 - 225
so, n(A U B) compliment = 105
Now,
probability = 105/330
Step-by-step explanation:
the solution is in the picture
Answer:
1312 miles
Step-by-step explanation:
To solve this, we simply need to subtract the distance she traveled in her trips to Chicago from the distance she traveled in her trips to Louisville.
She made 4 round trips to Chicago, Illinois. Each of the trips is a distance of 218 miles. This means that the total distance she traveled is:
4 * 218 = 872 miles
She made 6 round trips to Louisville, Kentucky/ Each of the trips is a distance of 364 miles. This means that the total distance she traveled is:
6 * 364 = 2184 miles
Therefore, the difference between the distances she traveled is:
2184 - 872 = 1312 miles
She traveled 1312 miles more in her trips to Louisville than in her trips to Chicago.
Answer: Sheila today = 
yrs old
<u>Step-by-step explanation:</u>
J + S = 115 v⇒ J = 115 - S
Current Ages Ages 14 years ago
Joe (J) = 115 - S J - 14 = 2(S - 14)
Sheila (S) = S
Substitute J = 115 - S into the "14 years ago" equation
J - 14 = 2(S - 14)
(115 - S) - 14 = 2(S - 14)
111 -S = 2S - 28
111 = 3S - 28
139 = 3S
46 
= S
It is odd that the result was not an integer. I wonder if you meant to type "Joe was twice as old as Sheila <u>is today</u>. That would change the equation to:
J - 14 = 2S
111 - S = 2S
111 = 3S
37 = S
