Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Help me I forgot what an exponent is help me pls.
19 27 28 29 30 315 64 29 46 is the
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Answer:
24xz + 28yz
Step-by-step explanation:
4z(6x + 7y) ← multiply each term in the parenthesis by 4z
= 24xz + 28yz
Answer:
x = 2
Step-by-step explanation:
2(2x+1-x)=6
2(x+1)=6 add common factors
2x+2=6 distribute the 2
2x=4 subrtract 2 on both sides
x=2 divide 2 on both sides
