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3 years ago

Find the sum of the first 12 terms of the sequence 512, 256, 128, … This is infinite series notation, the answer is NOT 896...

Mathematics

2 answers:

Kay [80]3 years ago

8 0

Answer:

1023.75

Step-by-step explanation:

sum = a( 1 - r^n) / (1-r)

a1 = 512

n = 12

r = 256 / 512 = 1/2

512 (1 - 1/2¹²)

therefore.. sum = ------------------ = 1023.75

1 - 1/2

postnew [5]3 years ago

7 0

Answer:

1023.75

Step-by-step explanation:

The sum of a geometric sequence is

sum = a( 1 - r^n) / (1-r)

where a is the first term r is the common ratio and r^n is the nth term

We need to find the common ratio

r = 256/512 = 1/2

sum = 512 ( 1 - 1/2^12) / ( 1-1/2)

=512( 1-.000244141) / (.5)

=512(.999755859) /.5

=1023.75

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Step-by-step explanation:

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Step-by-step explanation:

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